Arithmetic Progressions Class 10 Notes | Chapter 5 Maths

Vikash Sharma

Maths by Vikash Sharma

Expert Educator | Class 10


📘 Arithmetic Progressions Class 10 Notes (Chapter 5)

🔷 Introduction

Arithmetic Progression, also called AP, is an important topic in mathematics. In simple words, an arithmetic progression is a sequence of numbers where the difference between consecutive terms remains the same.

For example:

2, 5, 8, 11, 14…

Here, the common difference is 3.

Therefore, this sequence is an arithmetic progression.


🔹 What is Arithmetic Progression?

A sequence is called an arithmetic progression if:a2a1=a3a2=a4a3a_2-a_1 = a_3-a_2 = a_4-a_3a2​−a1​=a3​−a2​=a4​−a3​

This fixed difference is called the Common Difference (d).


🔹 Important Terms in AP

✔ First Term (a)

The first number of the sequence is called the first term.

Example:
In 3, 7, 11, 15…
First term = 3


✔ Common Difference (d)

The difference between two consecutive terms is called the common difference.

Formula:d=anan1d=a_n-a_{n-1}d=an​−an−1​

Example:

7−3 = 4

So, d = 4


✔ Number of Terms (n)

The total number of terms is represented by n.


🔷 General Form of AP

The general form of arithmetic progression is:a, a+d, a+2d, a+3d,a,\ a+d,\ a+2d,\ a+3d,\dotsa, a+d, a+2d, a+3d,…

Thus, every term can be found easily.


🔷 nth Term of AP

The nth term of an arithmetic progression is:an=a+(n1)da_n=a+(n-1)dan​=a+(n−1)d

Where:

  • a = first term
  • d = common difference
  • n = number of terms

🔹 Example of nth Term

Find the 10th term of:

2, 5, 8, 11…

Here:
a = 2
d = 3
n = 10

Using formula:an=a+(n1)da_n=a+(n-1)dan​=a+(n−1)d a10=2+(101)×3a_{10}=2+(10-1)\times3a10​=2+(10−1)×3 a10=2+27a_{10}=2+27a10​=2+27 a10=29a_{10}=29a10​=29

Hence, the 10th term is 29.


🔷 Sum of n Terms of AP

The sum of first n terms is:Sn=n2[2a+(n1)d]S_n=\frac{n}{2}[2a+(n-1)d]Sn​=2n​[2a+(n−1)d]

Another important formula is:Sn=n2(a+l)S_n=\frac{n}{2}(a+l)Sn​=2n​(a+l)

Where l is the last term.


🔹 Example of Sum Formula

Find the sum of first 5 terms:

2, 5, 8, 11, 14…

Here:
a = 2
d = 3
n = 5

Using formula:Sn=n2[2a+(n1)d]S_n=\frac{n}{2}[2a+(n-1)d]Sn​=2n​[2a+(n−1)d] S5=52[4+12]S_5=\frac{5}{2}[4+12]S5​=25​[4+12] S5=52×16S_5=\frac{5}{2}\times16S5​=25​×16 S5=40S_5=40S5​=40

Therefore, the sum is 40.


🔷 Important Properties of AP

✔ If d > 0

The sequence increases.

✔ If d < 0

The sequence decreases.

✔ If d = 0

All terms become equal.

As a result, the commo📘 Arithmetic Progressions Class 10 Notes (Chapter 5)

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